A closer look at the voting reveals that it really wasn't even that close; Bryant finished with the second-most first-team votes for a guard with 98 (trailing only Derrick Rose's 118), while Wade finished third overall among guards with a distant 24 first-team votes.
Bryant has now been selected to the All-NBA first team in nine of the past 10 seasons, and his nine first-team selections trail only Karl Malone (11), Bob Cousy (10), Bob Pettit (10), Jerry West (10), Kareem Abdul-Jabbar (10) and Michael Jordan (10).
Meanwhile, Wade has been selected to the first team just twice, in 2009 and 2010, yet many still seemed to question Bryant's first-team selection over Wade this past season.
A lot of it likely has to do with the fact that fans watched Wade play 21 games in the playoffs, including six games in the NBA Finals, while Bryant only played nine games—a result of the Lakers being swept by the NBA champion Dallas Mavericks in the second round. These same fans tend to forget the voting process actually takes place after the conclusion of the regular season and does not factor in playoff performance.
So let's figure this out based on five categories to settle this debate once and for all: Who is the best shooting guard in the league, Kobe or Wade?
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Article Source: Bleacher Report - Los Angeles Lakers
